Orbital eccentricity

An elliptic, parabolic and hyperbolic Kepler orbit:
      elliptic (eccentricity = 0.7)
      parabolic (eccentricity = 1)
      hyperbolic orbit (eccentricity = 1.3)

The orbital eccentricity of an astronomical object is a parameter that determines the amount by which its orbit around another body deviates from a perfect circle. A value of 0 is a circular orbit, values between 0 and 1 form an elliptical orbit, 1 is a parabolic escape orbit, and greater than 1 is a hyperbola. The term derives its name from the parameters of conic sections, as every Kepler orbit is a conic section. It is normally used for the isolated two-body problem, but extensions exist for objects following a rosette orbit through the galaxy.

Definition

In a two-body problem with inverse-square-law force, every orbit is a Kepler orbit. The eccentricity of this Kepler orbit is a non-negative number that defines its shape.

The eccentricity may take the following values:

circular orbit: $e=0\,\!$
elliptic orbit: $0<e<1\,\!$ (see Ellipse)
parabolic trajectory: $e=1\,\!$ (see Parabola)
hyperbolic trajectory: $e>1\,\!$ (see Hyperbola)

The eccentricity $e$ is given by

e = \sqrt{1 + \frac{2 E L^{2}}{m_\text{red} \alpha ^{2}}}

where E is the total orbital energy, $L$ is the angular momentum, $m_\text{red}$ is the reduced mass, and $\alpha$ the coefficient of the inverse-square law central force such as gravity or electrostatics in classical physics:

F = \frac{\alpha}{r^{2}}

( $\alpha$ is negative for an attractive force, positive for a repulsive one) (see also Kepler problem).

or in the case of a gravitational force:

e = \sqrt{1 + \frac{2 \epsilon h^{2}}{\mu^2}}

where $\epsilon$ is the specific orbital energy (total energy divided by the reduced mass), $\mu$ the standard gravitational parameter based on the total mass, and $h$ the specific relative angular momentum (angular momentum divided by the reduced mass).

For values of e from 0 to 1 the orbit's shape is an increasingly elongated (or flatter) ellipse; for values of e from 1 to infinity the orbit is a hyperbola branch making a total turn of 2 arccsc e, decreasing from 180 to 0 degrees. The limit case between an ellipse and a hyperbola, when e equals 1, is parabola.

Radial trajectories are classified as elliptic, parabolic, or hyperbolic based on the energy of the orbit, not the eccentricity. Radial orbits have zero angular momentum and hence eccentricity equal to one. Keeping the energy constant and reducing the angular momentum, elliptic, parabolic, and hyperbolic orbits each tend to the corresponding type of radial trajectory while e tends to 1 (or in the parabolic case, remains 1).

For a repulsive force only the hyperbolic trajectory, including the radial version, is applicable.

For elliptical orbits, a simple proof shows that arcsin( $e$ ) yields the projection angle of a perfect circle to an ellipse of eccentricity $e$ . For example, to view the eccentricity of the planet Mercury ( $e$ =0.2056), one must simply calculate the inverse sine to find the projection angle of 11.86 degrees. Next, tilt any circular object (such as a coffee mug viewed from the top) by that angle and the apparent ellipse projected to your eye will be of that same eccentricity.

Etymology

From Medieval Latin eccentricus, derived from Greek ekkentros "out of the center", from ek-, ex- "out of" + kentron "center". Eccentric first appeared in English in 1551, with the definition "a circle in which the earth, sun. etc. deviates from its center." Five years later, in 1556, an adjective form of the word was added.

Calculation

The eccentricity of an orbit can be calculated from the orbital state vectors as the magnitude of the eccentricity vector:

e= \left | \mathbf{e} \right |

where:

$\mathbf{e}\,\!$ is the eccentricity vector.

For elliptical orbits it can also be calculated from the periapsis and apoapsis since $r_p=a(1-e)$ and $r_a=a(1+e)$ , where $a$ is the semimajor axis.

e={{r_a-r_p}\over{r_a+r_p}}

=1-\frac{2}{(r_a/r_p)+1}

where:

$r_a\,\!$ is the radius at apoapsis (i.e., the farthest distance of the orbit to the center of mass of the system, which is a focus of the ellipse).
$r_p\,\!$ is the radius at periapsis (the closest distance).

The eccentricity of an elliptical orbit can also be used to obtain the ratio of the periapsis to the apoapsis:

{{r_p}\over{r_a}}={{1-e}\over{1+e}}

Examples

Gravity Simulator plot of the changing orbital eccentricity of Mercury, Venus, Earth, and Mars over the next 50,000 years. The arrows indicate the different scales used. The 0 point on this plot is the year 2007.

The eccentricity of the Earth's orbit is currently about 0.0167; the Earth's orbit is nearly circular. Over hundreds of thousands of years, the eccentricity of the Earth's orbit varies from nearly 0.0034 to almost 0.058 as a result of gravitational attractions among the planets (see graph).^[1]

Mercury has the greatest orbital eccentricity of any planet in the Solar System (e=0.2056). Before 2006, Pluto was considered to be the planet with the most eccentric orbit (e=0.248). The Moon's value is 0.0549. For the values for all planets and other celestial bodies in one table, see List of gravitationally rounded objects of the Solar System. Sedna the most distant known Trans-Neptunian object in the Solar System has an extremely high eccentricity of 0.85491 due to which it has an aphelion estimated at 937 AU and a perihelion at about 76 AU.

Most of the Solar System's asteroids have orbital eccentricities between 0 and 0.35 with an average value of 0.17.^[2] Their comparatively high eccentricities are probably due to the influence of Jupiter and to past collisions.

Comets have very different values of eccentricity. Periodic comets have eccentricities mostly between 0.2 and 0.7,^[3] but some of them have highly eccentric elliptical orbits with eccentricities just below 1, for example, Halley's Comet has a value of 0.967. Non-periodic comets follow near-parabolic orbits and thus have eccentricities even closer to 1. Examples include Comet Hale–Bopp with a value of 0.995^[4] and comet C/2006 P1 (McNaught) with a value of 1.000019.^[5] As Hale–Bopp's value is less than 1, its orbit is elliptical and it will in fact return.^[4] Comet McNaught has a hyperbolic orbit while within the influence of the planets, but is still bound to the Sun with an orbital period of about 10⁵ years.^[6] As of a 2010 Epoch, Comet C/1980 E1 has the largest eccentricity of any known hyperbolic comet with an eccentricity of 1.057,^[7] and will leave the Solar System indefinitely.

Neptune's largest moon Triton has an eccentricity of 1.6 × 10⁻⁵,^[8] the smallest eccentricity of any known body in the Solar System; its orbit is as close to a perfect circle as can be currently measured.

Mean eccentricity

The mean eccentricity of an object is the average eccentricity as a result of perturbations over a given time period. Neptune currently has an instant (current Epoch) eccentricity of 0.0113,^[9] but from 1800 A.D. to 2050 A.D. has a mean eccentricity of 0.00859.^[10]

Climatic effect

Orbital mechanics require that the duration of the seasons be proportional to the area of the Earth's orbit swept between the solstices and equinoxes, so when the orbital eccentricity is extreme, the seasons that occur on the far side of the orbit (aphelion) can be substantially longer in duration. Today, northern hemisphere fall and winter occur at closest approach (perihelion), when the earth is moving at its maximum velocity—while the opposite occurs in the southern hemisphere. As a result, in the northern hemisphere, fall and winter are slightly shorter than spring and summer—but in global terms this is balanced with them being longer below the equator. In 2006, the northern hemisphere summer was 4.66 days longer than winter and spring was 2.9 days longer than fall.^[11]^{[citation needed]} Apsidal precession slowly changes the place in the Earth's orbit where the solstices and equinoxes occur (this is not the precession of the axis). Over the next 10,000 years, northern hemisphere winters will become gradually longer and summers will become shorter. Any cooling effect in one hemisphere is balanced by warming in the other—and any overall change will, however, be counteracted by the fact that the eccentricity of Earth's orbit will be almost halved^{[citation needed]}, reducing the mean orbital radius and raising temperatures in both hemispheres closer to the mid-interglacial peak.

References

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↑ Asteroids
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↑ This information is concerning the summer of the year 2006 not the current year we are in now.