1940 United States presidential election in Nebraska

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1940 United States presidential election in Nebraska

← 1936 November 5, 1940[1] 1944 →

All 7 Nebraska votes to the Electoral College
  160x160px FDRoosevelt1938.png
Nominee Wendell Willkie Franklin D. Roosevelt
Party Republican Democratic
Home state Indiana New York
Running mate Charles L. McNary Henry A. Wallace
Electoral vote 7 0
Popular vote 352,201 263,677
Percentage 57.2% 42.8%

President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

The 1940 United States presidential election in Nebraska took place on November 5, 1940, as part of the 1940 United States presidential election. Voters chose seven[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Nebraska was won by Wendell Willkie (RIndiana), running with Minority Leader Charles L. McNary, with 57.19% of the popular vote, against incumbent President Franklin D. Roosevelt (DNew York), running with Secretary Henry A. Wallace, with 42.81% of the popular vote.[3][4]

With 57.19% of the popular vote, Nebraska would prove to be Willkie's second strongest state in the 1940 election in terms of popular vote percentage after neighboring South Dakota.[5]

Results

1940 United States presidential election in Nebraska
Party Candidate Votes %
Republican Wendell Willkie 352,201 57.19%
Democratic Franklin D. Roosevelt (inc.) 263,677 42.81%
Total votes 615,878 100%

References

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