File:Dopplereffectsourcemovingrightatmach1.4.gif
Summary
The sound source has now broken through the sound speed barrier, and is traveling at 1.4 times the speed of sound, c (Mach 1.4). Since the source is moving faster than the sound waves it creates, it actually leads the advancing wavefront. The sound source will pass by a stationary observer before the observer actually hears the sound it creates. As a result, an observer in front of the source will detect <img src="https://wikimedia.org/api/rest_v1/media/math/render/svg/a0bb98d0652d98508b24a33fed9bb59d7b097075" class="mwe-math-fallback-image-inline mw-math-element" aria-hidden="true" style="vertical-align: -2.505ex; width:27.821ex; height:6.176ex;" alt="{\displaystyle f=\left({\frac {c+v_{r}}{c-v_{s}}}\right)f_{0}=-2.5f_{0}\,}"> and an observer behind the source <img src="https://wikimedia.org/api/rest_v1/media/math/render/svg/b915888db80dcfa356c66b7f7da7e3a9ceb61edc" class="mwe-math-fallback-image-inline mw-math-element" aria-hidden="true" style="vertical-align: -2.505ex; width:27.175ex; height:6.176ex;" alt="{\displaystyle f=\left({\frac {c-v_{r}}{c+v_{s}}}\right)f_{0}=0.42f_{0}\,}">.
Licensing
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| Date/Time | Thumbnail | Dimensions | User | Comment | |
|---|---|---|---|---|---|
| current | 01:43, 6 January 2017 | | 301 × 298 (214 KB) | 127.0.0.1 (talk) | The sound source has now broken through the sound speed barrier, and is traveling at 1.4 times the speed of sound, c (Mach 1.4). Since the source is moving faster than the sound waves it creates, it actually leads the advancing wavefront. The sound source will pass by a stationary observer before the observer actually hears the sound it creates. As a result, an observer in front of the source will detect <span><span class="mwe-math-mathml-inline mwe-math-mathml-a11y mw-math-element" style="display: none;"><math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow class="MJX-TeXAtom-ORD"><mstyle displaystyle="true" scriptlevel="0"><mi>f</mi><mo>=</mo><mrow><mo>(</mo><mrow class="MJX-TeXAtom-ORD"><mfrac><mrow><mi>c</mi><mo>+</mo><msub><mi>v</mi><mrow class="MJX-TeXAtom-ORD"><mi>r</mi></mrow></msub></mrow><mrow><mi>c</mi><mo>−<!-- − --></mo><msub><mi>v</mi><mrow class="MJX-TeXAtom-ORD"><mi>s</mi></mrow></msub></mrow></mfrac></mrow><mo>)</mo></mrow><msub><mi>f</mi><mrow class="MJX-TeXAtom-ORD"><mn>0</mn></mrow></msub><mo>=</mo><mo>−<!-- − --></mo><mn>2.5</mn><msub><mi>f</mi><mrow class="MJX-TeXAtom-ORD"><mn>0</mn></mrow></msub><mspace width="thinmathspace"></mspace></mstyle></mrow><annotation encoding="application/x-tex">{\displaystyle f=\left({\frac {c+v_{r}}{c-v_{s}}}\right)f_{0}=-2.5f_{0}\,}</annotation></semantics></math></span><img src="https://wikimedia.org/api/rest_v1/media/math/render/svg/a0bb98d0652d98508b24a33fed9bb59d7b097075" class="mwe-math-fallback-image-inline mw-math-element" aria-hidden="true" style="vertical-align: -2.505ex; width:27.821ex; height:6.176ex;" alt="{\displaystyle f=\left({\frac {c+v_{r}}{c-v_{s}}}\right)f_{0}=-2.5f_{0}\,}"></span> and an observer behind the source <span><span class="mwe-math-mathml-inline mwe-math-mathml-a11y mw-math-element" style="display: none;"><math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow class="MJX-TeXAtom-ORD"><mstyle displaystyle="true" scriptlevel="0"><mi>f</mi><mo>=</mo><mrow><mo>(</mo><mrow class="MJX-TeXAtom-ORD"><mfrac><mrow><mi>c</mi><mo>−<!-- − --></mo><msub><mi>v</mi><mrow class="MJX-TeXAtom-ORD"><mi>r</mi></mrow></msub></mrow><mrow><mi>c</mi><mo>+</mo><msub><mi>v</mi><mrow class="MJX-TeXAtom-ORD"><mi>s</mi></mrow></msub></mrow></mfrac></mrow><mo>)</mo></mrow><msub><mi>f</mi><mrow class="MJX-TeXAtom-ORD"><mn>0</mn></mrow></msub><mo>=</mo><mn>0.42</mn><msub><mi>f</mi><mrow class="MJX-TeXAtom-ORD"><mn>0</mn></mrow></msub><mspace width="thinmathspace"></mspace></mstyle></mrow><annotation encoding="application/x-tex">{\displaystyle f=\left({\frac {c-v_{r}}{c+v_{s}}}\right)f_{0}=0.42f_{0}\,}</annotation></semantics></math></span><img src="https://wikimedia.org/api/rest_v1/media/math/render/svg/b915888db80dcfa356c66b7f7da7e3a9ceb61edc" class="mwe-math-fallback-image-inline mw-math-element" aria-hidden="true" style="vertical-align: -2.505ex; width:27.175ex; height:6.176ex;" alt="{\displaystyle f=\left({\frac {c-v_{r}}{c+v_{s}}}\right)f_{0}=0.42f_{0}\,}"></span>. |
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